use the exponent function on your calculator (ee or exp) to compute the following.

6.02 x 10^23) (-5.11 x 10-27)
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-8.23 x 10^5

1 answer

To compute the expression \((6.02 \times 10^{23}) \cdot (-5.11 \times 10^{-27})\) and then divide by \(-8.23 \times 10^5\), you can follow these steps:

  1. Multiply the two numbers in the numerator:

    • Multiply the coefficients: \(6.02 \times -5.11\)
    • Multiply the powers of ten: \(10^{23} \times 10^{-27} = 10^{(23 - 27)} = 10^{-4}\)
  2. Calculate the coefficient: \[ 6.02 \times -5.11 = -30.7572 \]

  3. Combine the results: \[ (6.02 \times 10^{23}) \cdot (-5.11 \times 10^{-27}) = -30.7572 \times 10^{-4} = -3.07572 \times 10^{-3} \]

  4. Now, divide by \(-8.23 \times 10^{5}\):

    • Divide the coefficients: \(-3.07572 \div -8.23\)
    • Divide the powers of ten: \(10^{-3} \div 10^{5} = 10^{(-3 - 5)} = 10^{-8}\)
  5. Calculate the coefficient: \[ -3.07572 \div -8.23 \approx 0.374 \]

  6. Combine these results: \[ \frac{-3.07572 \times 10^{-3}}{-8.23 \times 10^{5}} \approx 0.374 \times 10^{-8} \]

  7. Express in proper scientific notation: \[ 0.374 \times 10^{-8} = 3.74 \times 10^{-9} \]

So the final result is:

\[ \approx 3.74 \times 10^{-9} \]