Use the equation y-5=x/3 to fill in the missing values in the table below

Answer 1

To fill in the missing values using the equation \( y - 5 = \frac{x}{3} \), we can rearrange the equation to solve for \( y \):

\[ y = \frac{x}{3} + 5 \]

Now, we can input various values for \(x\) to find the corresponding \(y\) values.

Please provide the values of \(x\) or the incomplete table you mentioned so that I can help fill in the missing values.

Answer 2

X y
_ 1
-3 4
0 _
6 _
_ 8

0,7,5,1,-12,12,9

Answer 3

Let's use the equation \( y - 5 = \frac{x}{3} \) or, equivalently, \( y = \frac{x}{3} + 5 \) to find the missing values for \(y\) based on the provided \(x\) values.

We will use the values you provided: \(0, 7, 5, 1, -12, 12, 9\) to find the matches.

Filling Out the Table

1. For \( x = _ \), \( y = 1 \): \[ 1 = \frac{x}{3} + 5 \] \[ \frac{x}{3} = 1 - 5 \Rightarrow \frac{x}{3} = -4 \Rightarrow x = -12 \]

2. For \( x = -3 \), \( y = 4\) (already given, for checking): \[ 4 = \frac{-3}{3} + 5 \Rightarrow 4 = -1 + 5 \Rightarrow \text{True} \]

3. For \( x = 0 \), \( y = _ \): \[ y = \frac{0}{3} + 5 = 5 \]

4. For \( x = 6 \), \( y = _ \): \[ y = \frac{6}{3} + 5 = 2 + 5 = 7 \]

5. For \( x = _ \), \( y = 8 \): \[ 8 = \frac{x}{3} + 5 \] \[ \frac{x}{3} = 8 - 5 \Rightarrow \frac{x}{3} = 3 \Rightarrow x = 9 \]

Completed Table

Here’s the completed table with all the values filled in:

\[ \begin{array}{|c|c|} \hline X & Y \ \hline -12 & 1 \ -3 & 4 \ 0 & 5 \ 6 & 7 \ 9 & 8 \ \hline \end{array} \]

So the missing values are:

• For the first row: \( x = -12 \)
• For the third row: \( y = 5 \)
• For the fourth row: \( y = 7 \)
• For the last row: \( x = 9 \)

Let me know if you need any further assistance!

Answer 4

Are you positive

Answer 5

Let's carefully verify the calculations for the values in the table one more time using the equation \( y - 5 = \frac{x}{3} \) (or \( y = \frac{x}{3} + 5 \)).

Given Table for Verification

| x | y | |-----|-----| | _ | 1 | | -3 | 4 | | 0 | _ | | 6 | _ | | _ | 8 |

Step-by-Step Calculation

1. For the first row where \( y = 1 \): \[ 1 = \frac{x}{3} + 5 \] \[ \frac{x}{3} = 1 - 5 \Rightarrow \frac{x}{3} = -4 \Rightarrow x = -12 \]

2. For the second row where \( x = -3 \): \[ y = \frac{-3}{3} + 5 = -1 + 5 = 4 \quad (\text{This is correct.}) \]

3. For the third row where \( x = 0 \): \[ y = \frac{0}{3} + 5 = 5 \]

4. For the fourth row where \( x = 6 \): \[ y = \frac{6}{3} + 5 = 2 + 5 = 7 \]

5. For the fifth row where \( y = 8 \): \[ 8 = \frac{x}{3} + 5 \] \[ \frac{x}{3} = 8 - 5 \Rightarrow \frac{x}{3} = 3 \Rightarrow x = 9 \]

Completed Table Verification

After double-checking the calculations, the values are confirmed as follows:

| x | y | |-----|-----| | -12 | 1 | | -3 | 4 | | 0 | 5 | | 6 | 7 | | 9 | 8 |

Summary of Missing Values:

• For \( y = 1 \), \( x = -12 \)
• For \( x = 0 \), \( y = 5 \)
• For \( x = 6 \), \( y = 7 \)
• For \( y = 8 \), \( x = 9 \)

Based on these calculations, I can confirm that the previous answer is accurate. If you have additional concerns or would like to explore further, please let me know!