To balance the equation \( \text{CH}_4 + ____ \text{Cl}_2 \rightarrow \text{CCl}_4 + ____ \text{HCl} \), we first identify the number of each type of atom on both sides of the equation.
On the left side:
- Carbon (C): 1 (from CH₄)
- Hydrogen (H): 4 (from CH₄)
- Chlorine (Cl): 2 (from Cl₂)
On the right side:
- Carbon (C): 1 (from CCl₄)
- Hydrogen (H): 1 (from HCl)
- Chlorine (Cl): 4 (from CCl₄) + 1 (from HCl) = 5
To balance it, we can trial and error with the provided options.
Testing the options:
-
Option (4, 4):
- 4 CH₄ + 4 Cl₂ → 4 CCl₄ + 4 HCl
- Left: C = 4, H = 16, Cl = 8
- Right: C = 4, H = 4, Cl = 16
- Not balanced.
-
Option (3, 2):
- 3 CH₄ + 2 Cl₂ → 3 CCl₄ + 2 HCl
- Left: C = 3, H = 12, Cl = 4
- Right: C = 3, H = 2, Cl = 14
- Not balanced.
-
Option (2, 4):
- 2 CH₄ + 4 Cl₂ → 2 CCl₄ + 4 HCl
- Left: C = 2, H = 8, Cl = 8
- Right: C = 2, H = 4, Cl = 8
- Not balanced.
-
Option (1, 2):
- 1 CH₄ + 2 Cl₂ → 1 CCl₄ + 2 HCl
- Left: C = 1, H = 4, Cl = 4
- Right: C = 1, H = 2, Cl = 6
- Not balanced.
Correct Balancing:
Let's try balancing it directly to find if a straightforward approach shows us the answer: To balance:
- Chlorine: CCl₄ has 4 Cl, so we need 2 Cl₂ (since each Cl₂ gives 2 Cl).
- Hydrogen: We will need 4 HCl for 4 H.
Final Balanced Equation:
- Therefore, 1 CH₄ + 2 Cl₂ → 1 CCl₄ + 4 HCl.
Looks like I miscomputed previously; reviewing the equation, we notice:
The numbers that balance the original equation accurately are:
- 1, 4 for CH₄ & HCl respectively.
Thus the correct answer isn't listed explicitly among your options, however 1 and 4 would be the correct combination to balance if they were present.
If I strictly follow provided pairs, it's evident that: The balanced answer set (1, 4) isn't present in the multiple choice responses, further correcting confirms an error in logical extrapolation from provided or implied conditions. Thus: Reviewing acceptable responses lists significant errors, check reevaluation of setup or probable amendments for clarity adjustments; choice exempts and correct predictors align.