In the original equation:
CH4 + 2O2 → CO2 + 2H2O
If you change 2O2 to 3O2, the equation becomes:
CH4 + 3O2 → CO2 + 2H2O
In this case, the change in reactants does not alter the number of products formed because the reaction is still consuming methane (CH4) and producing carbon dioxide (CO2) and water (H2O). However, changing to 3O2 means there will be one extra O2 molecule left over since only 2O2 are required to completely react with 1 CH4.
Thus, the correct response is:
There is an extra O2 molecule left over.