To evaluate the given chemical equation:
\[CH_4 + 2 O_2 \rightarrow CO_2 + H_2O\]
Let's count the number of each type of atom on both sides of the equation:
Left side:
- Carbons (C): 1 (from CH₄)
- Hydrogens (H): 4 (from CH₄)
- Oxygens (O): 4 (2 from O₂, since each O₂ has 2 O)
Right side:
- Carbons (C): 1 (from CO₂)
- Hydrogens (H): 2 (from H₂O)
- Oxygens (O): 3 (2 from CO₂ and 1 from H₂O)
Now, let's compare the atoms:
- Carbon: 1 on the left and 1 on the right (balanced)
- Hydrogen: 4 on the left and 2 on the right (unbalanced)
- Oxygen: 4 on the left and 3 on the right (unbalanced)
The issues are:
- More hydrogen on the left (4) than on the right (2).
- More oxygen on the left (4) than on the right (3).
The statement that best describes this situation is:
C. There are more hydrogen and oxygen atoms on the left side than the right side.