Question

Use the equation of motion to answer the question.
x = x0 + vot + {at?
An object has a starting position of x = 2 m, a starting
velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s?
(1 point)
• 18 m
• 11 m
09 m
0 5.5 m

Answer 1

Given the equation of motion:

\[
x = x_0 + v_0 t + \frac{1}{2} a t^2
\]

where:
- \(x\) is the final position,
- \(x_0\) is the initial position,
- \(v_0\) is the initial velocity,
- \(a\) is the acceleration,
- \(t\) is the time.

In this case:
- \(x_0 = 2 \, \text{m}\)
- \(v_0 = 4.5 \, \text{m/s}\)
- \(a = 0 \, \text{m/s}^2\) (no acceleration)
- \(t = 2 \, \text{s}\)

Since the acceleration is zero, the equation simplifies to:

\[
x = x_0 + v_0 t
\]

Substituting in the values:

\[
x = 2 \, \text{m} + (4.5 \, \text{m/s} \times 2 \, \text{s})
\]
\[
x = 2 \, \text{m} + 9 \, \text{m}
\]
\[
x = 11 \, \text{m}
\]

Thus, the final position of the object after 2 seconds is **11 m**.