Use the equation for the formation of water to answer the question. 2H2 + O2 → 2H2O Elements such as oxygen and hydrogen naturally exist as diatomic molecules (i.e., in a paired-atom form). Does the equation for the formation of water violate the law of conservation of mass? Why or why not? (1 point) Responses No, it does not because there are two water molecules, so the bonds within the diatomic molecules were not broken. No, it does not because there are two water molecules, so the bonds within the diatomic molecules were not broken. Yes, it does because there are two oxygen atoms in the reactants and only one in the product. Yes, it does because there are two oxygen atoms in the reactants and only one in the product. No, it does not because the number and mass of atoms are conserved even though the number of molecules is not. No, it does not because the number and mass of atoms are conserved even though the number of molecules is not. Yes, it does because the diatomic oxygen molecule is not present on both sides of the equation.

Answer 1

No, it does not because the number and mass of atoms are conserved even though the number of molecules is not.

In the given equation, 2H2 + O2 → 2H2O, there are 4 hydrogen atoms and 2 oxygen atoms on the reactant side and 4 hydrogen atoms and 2 oxygen atoms on the product side. Therefore, the law of conservation of mass is upheld as the total number of each type of atom remains the same before and after the reaction.