Use the equation for motion to answer the question.

Question

x=x0+v0t+12at2
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An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?

(1 point)
Responses

30 m
30 m

17 m
17 m

32 m
32 m

60 m

Answer 1

Since the object is moving at a constant speed, the acceleration (\(a\)) is 0. Thus, we can simplify the motion equation:

\[ x = x_0 + v_0 t + \frac{1}{2} a t^2 \]

Substituting \(a = 0\):

\[ x = x_0 + v_0 t \]

Given:

• \(x_0 = 2 , \text{m}\) (starting position)
• \(v_0 = 15 , \text{m/s}\) (starting velocity)
• \(t = 1 , \text{s}\) (time elapsed)

Now we can plug in the values:

\[ x = 2 , \text{m} + (15 , \text{m/s} \cdot 1 , \text{s}) \] \[ x = 2 , \text{m} + 15 , \text{m} = 17 , \text{m} \]

Therefore, the final position of the object after 1 second is 17 m.