Use the equation for motion to answer the question.

x=x0+v0t+12at2


An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?

(1 point)
Responses

60 m
60 m

32 m
32 m

30 m
30 m

17 m

1 answer

In the equation for motion \( x = x_0 + v_0 t + \frac{1}{2} a t^2 \):

  • \( x_0 \) is the initial position
  • \( v_0 \) is the initial velocity
  • \( a \) is the acceleration
  • \( t \) is the time

Given in the problem:

  • Initial position \( x_0 = 2 \) m
  • Initial velocity \( v_0 = 15 \) m/s
  • Since the object is moving at a constant speed, the acceleration \( a = 0 \) m/s².
  • Time \( t = 1 \) s

Now, substituting these values into the equation:

\[ x = 2 + 15(1) + \frac{1}{2}(0)(1^2) \]

This simplifies to:

\[ x = 2 + 15 + 0 \]

\[ x = 17 , \text{m} \]

Therefore, the final position of the object after 1 second is 17 m.

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