To find the final position of the object after 1 second, we can use the motion equation:
\[ x = x_0 + v_0 t + \frac{1}{2} a t^2 \]
Given:
- Starting position, \( x_0 = 2 \) m
- Starting velocity, \( v_0 = 15 \) m/s
- The object is moving at a constant speed, which means the acceleration \( a = 0 \) m/s².
- Time, \( t = 1 \) s
Substituting the values into the equation:
\[ x = 2 , \text{m} + (15 , \text{m/s})(1 , \text{s}) + \frac{1}{2} (0 , \text{m/s}^2)(1 , \text{s})^2 \]
Since the acceleration term is zero, it simplifies to:
\[ x = 2 , \text{m} + 15 , \text{m} \] \[ x = 17 , \text{m} \]
Thus, the final position of the object after 1 second is 17 m.
So the correct response is:
17 m