Use the equation for motion to answer the question.

Question

x = x0 + v0t + 1/2 at^2

An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?
A) 30 m
B) 60 m
C) 32 m
D) 17 m

Answer 1

Since the object is moving at a constant speed, the acceleration \( a \) is 0. Therefore, the equation for motion simplifies to:

\[ x = x_0 + v_0 t \]

Where:

• \( x_0 = 2 , \text{m} \) (starting position)
• \( v_0 = 15 , \text{m/s} \) (starting velocity)
• \( t = 1 , \text{s} \)

Now substituting the values into the equation:

\[ x = 2 , \text{m} + (15 , \text{m/s} \cdot 1 , \text{s}) \]

\[ x = 2 , \text{m} + 15 , \text{m} \]

\[ x = 17 , \text{m} \]

Therefore, the final position of the object after 1 second is:

D) 17 m