Use the equation 4x+8= 40/y to fill in the missing values in the table below

Answer 1

To fill in the missing values in the table, we can substitute the given values of x into the equation and solve for y.

| x | y |
|---|---|
| 1 | |
| 2 | |
| 3 | |

For x = 1:
4(1) + 8 = 40/y
4 + 8 = 40/y
12 = 40/y

To find y, we can multiply both sides of the equation by y:
12y = 40

Divide both sides of the equation by 12:
y = 40/12
y = 10/3

So, when x = 1, y = 10/3.

Now, let's find y for x = 2:
4(2) + 8 = 40/y
8 + 8 = 40/y
16 = 40/y

Multiply both sides of the equation by y:
16y = 40

Divide both sides of the equation by 16:
y = 40/16
y = 5/2

Therefore, when x = 2, y = 5/2.

Finally, let's find y for x = 3:
4(3) + 8 = 40/y
12 + 8 = 40/y
20 = 40/y

Multiply both sides of the equation by y:
20y = 40

Divide both sides of the equation by 20:
y = 40/20
y = 2

Therefore, when x = 3, y = 2.

The completed table is:

| x | y |
|---|-------|
| 1 | 10/3 |
| 2 | 5/2 |
| 3 | 2 |