To verify which expression is equivalent to \((x-5)(x-3)\), we will use the Distributive Property to expand the expression:
\[ (x-5)(x-3) = x(x-3) - 5(x-3) \]
Expanding each term:
- \(x(x - 3) = x^2 - 3x\)
- \(-5(x - 3) = -5x + 15\)
Now, combine these results:
\[ x^2 - 3x - 5x + 15 = x^2 - 8x + 15 \]
Thus, the expansion gives us:
\[ (x-5)(x-3) = x^2 - 8x + 15 \]
Now, let’s compare \(x^2 - 8x + 15\) with the given options:
- \(3x^{2}-4x^{2}-3x-15\) simplifies to \(-x^2 - 3x - 15\)
- \(x^{2}-2x+15\) remains \(x^2 - 2x + 15\)
- \(x^{2}-8x+15\) matches exactly \(x^2 - 8x + 15\)
- \(2x-2\) remains \(2x - 2\)
The expression that is equivalent to \((x-5)(x-3)\) is:
\[ \boxed{x^{2}-8x+15} \]