Use the Distributive Property to rewrite the polynomial (x + 8)(x - 2)

Box x ^ 2 + Box x+ Box

1 answer

To use the Distributive Property to rewrite the polynomial \((x + 8)(x - 2)\), we will distribute each term in the first binomial \((x + 8)\) to each term in the second binomial \((x - 2)\).

Here are the steps:

  1. Distribute \(x\) to both \(x\) and \(-2\): \[ x \cdot x + x \cdot (-2) = x^2 - 2x \]

  2. Distribute \(8\) to both \(x\) and \(-2\): \[ 8 \cdot x + 8 \cdot (-2) = 8x - 16 \]

  3. Combine all the terms from the distributions: \[ x^2 - 2x + 8x - 16 \]

  4. Combine like terms: \[ x^2 + 6x - 16 \]

Now, we can fill in the boxes:

\[ \text{Box} , x^2 + \text{Box} , 6x + \text{Box} , (-16) \]

So, the final rewritten polynomial is: \[ x^2 + 6x - 16 \]

The filled-in boxes will be:

  • Box for \(x^2\): 1 (since it can be written as \(1x^2\))
  • Box for \(6x\): 6
  • Box for \(-16\): -16