To prove that the two algebraic expressions are equivalent using the distributive property, we'll simplify both expressions step by step.
Expression 1: \( x - 5(x + 3) \)
- Distributing \(-5\) in the expression: \[ x - 5(x + 3) = x - 5x - 15 \]
- Combine like terms: \[ x - 5x - 15 = -4x - 15 \]
Expression 2: \( 2x^2 - x^2 - 2x - 20 + 5 \)
- Combine \(2x^2\) and \(-x^2\): \[ 2x^2 - x^2 = x^2 \]
- Now rewrite the expression: \[ x^2 - 2x - 20 + 5 \]
- Combine the constants \(-20\) and \(5\): \[ -20 + 5 = -15 \]
- Final expression: \[ x^2 - 2x - 15 \]
Now, let's rewrite both simplified expressions:
- Expression 1 simplified is \(-4x - 15\).
- Expression 2 simplified is \(x^2 - 2x - 15\).
Conclusion:
The expressions \(x - 5(x + 3)\) simplifies to \(-4x - 15\), and \(2x^2 - x^2 - 2x - 20 + 5\) simplifies to \(x^2 - 2x - 15\). Since there are different degrees (\(-4x - 15\) is linear while \(x^2 - 2x - 15\) is quadratic), these expressions are not equivalent. Thus, they represent distinct expressions in algebra.