To determine the number of real solutions of the equation \(3x^2 = 16x + 12\), we can first rewrite it in the standard form of a quadratic equation:
\[ 3x^2 - 16x - 12 = 0 \]
In this equation, \(a = 3\), \(b = -16\), and \(c = -12\).
Next, we calculate the discriminant \(D\) using the formula:
\[ D = b^2 - 4ac \]
Substituting in the values of \(a\), \(b\), and \(c\):
\[ D = (-16)^2 - 4 \cdot 3 \cdot (-12) \] \[ D = 256 + 144 \] \[ D = 400 \]
Since the discriminant \(D = 400\) is positive, it indicates that there are two distinct real solutions.
Thus, the correct statement is:
There will be two real solutions since the discriminant is positive.