To determine the number of real solutions for the quadratic equation \(4x^2 + 3x - 7 = 0\), we need to calculate the discriminant, which is given by the formula:
\[ D = b^2 - 4ac \]
For the equation \(4x^2 + 3x - 7\),
- \(a = 4\)
- \(b = 3\)
- \(c = -7\)
Now, plugging in these values into the discriminant formula:
\[ D = (3)^2 - 4(4)(-7) \] \[ D = 9 - 4 \cdot 4 \cdot (-7) \] \[ D = 9 + 112 \] \[ D = 121 \]
Since the discriminant \(D = 121\) is positive, this means there are two real solutions for the equation.
Therefore, the correct statement is:
There will be two real solutions since the discriminant is positive.