To determine the number of real solutions for the quadratic equation \(4x^2 + 3x - 7 = 0\), we start by calculating the discriminant, which is given by the formula:
\[ D = b^2 - 4ac \]
In this equation, \(a = 4\), \(b = 3\), and \(c = -7\). Plugging these values into the discriminant formula:
\[ D = (3)^2 - 4(4)(-7) \] \[ D = 9 - 4 \cdot 4 \cdot (-7) \] \[ D = 9 - (-112) \] \[ D = 9 + 112 \] \[ D = 121 \]
Since the discriminant \(D = 121\) is positive, this indicates that there are two real solutions.
Therefore, the correct response is:
There will be two real solutions since the discriminant is positive.