To determine the number of real solutions for the equation \( 3x^2 = 16x + 12 \), we first need to rewrite it in standard quadratic form:
\[ 3x^2 - 16x - 12 = 0 \]
Next, we identify the coefficients:
- \( a = 3 \)
- \( b = -16 \)
- \( c = -12 \)
The discriminant \( D \) of a quadratic equation \( ax^2 + bx + c = 0 \) is calculated using the formula:
\[ D = b^2 - 4ac \]
Now, we calculate the discriminant:
\[ D = (-16)^2 - 4(3)(-12) \] \[ D = 256 + 144 \] \[ D = 400 \]
Since the discriminant \( D = 400 \) is positive, it indicates that there are two distinct real solutions to the equation.
Therefore, the correct explanation is: There will be two real solutions since the discriminant is positive.