discriminant= b2-4ac
(8)^2-4(1)(16)
64-64=0
One real root (because it equals 0).
If it was a positive number, there would be two real roots. If it was a negative number, there would be two COMPLEX roots.
Use the discriminant to determine how many real number solutions the equation has.
t^2 + 8t + 16 = 0
1 answer