for all x ≠ -3, (x^2-9)/(x+3) = x-3
So, the limit as x->0 is just -3.
How did you get -6?
Use the definition of limits to show that
Lim x➡ 0 : (x^2 - 9) / (x + 3) = -6
hence find the number d > 0 given that e=0.05
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