To find the missing acceleration value in the table, we can use Newton's second law of motion, which states that \( F = m \cdot a \), where \( F \) is the net force, \( m \) is the mass, and \( a \) is the acceleration.
From the given data:
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For the first row:
- Net force \( F = 5.0 , \text{N} \)
- Mass \( m = 5.0 , \text{kg} \)
- Acceleration \( a = 1.0 , \text{m/s}^2 \)
Check: \( 5.0 = 5.0 \cdot 1.0 \) (Correct)
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For the second row:
- Net force \( F = 10.0 , \text{N} \)
- Mass \( m = 5.0 , \text{kg} \)
- Acceleration \( a = 2.0 , \text{m/s}^2 \)
Check: \( 10.0 = 5.0 \cdot 2.0 \) (Correct)
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For the third row:
- Net force \( F = 20.0 , \text{N} \)
- Mass \( m = 5.0 , \text{kg} \)
- Acceleration \( a = ? \)
Using the formula \( a = \frac{F}{m} \):
\[ a = \frac{20.0 , \text{N}}{5.0 , \text{kg}} = 4.0 , \text{m/s}^2 \]
Thus, the value that would complete the last cell is 4.0.