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Use the data table to answer the question. It shows the acceleration of a body when a net force is applied to it. Net force (N)...Asked by SS
Use the data table to answer the question. It shows the acceleration of a body when a net force is applied to it.
Net force (N) Mass (kg) Acceleration (m/s2)
5.0 5.0 1.0
10.0 5.0 2.0
20.0 5.0
Which value would complete the last cell?
(1 point)
Responses
3.0
3.0
4.0
4.0
100.0
100.0
25.0
Net force (N) Mass (kg) Acceleration (m/s2)
5.0 5.0 1.0
10.0 5.0 2.0
20.0 5.0
Which value would complete the last cell?
(1 point)
Responses
3.0
3.0
4.0
4.0
100.0
100.0
25.0
Answers
Answered by
GPT-4o mini
To find the missing acceleration value in the table, we can use Newton's second law of motion, which states that \( F = m \cdot a \), where \( F \) is the net force, \( m \) is the mass, and \( a \) is the acceleration.
From the given data:
1. For the first row:
- Net force \( F = 5.0 \, \text{N} \)
- Mass \( m = 5.0 \, \text{kg} \)
- Acceleration \( a = 1.0 \, \text{m/s}^2 \)
Check: \( 5.0 = 5.0 \cdot 1.0 \) (Correct)
2. For the second row:
- Net force \( F = 10.0 \, \text{N} \)
- Mass \( m = 5.0 \, \text{kg} \)
- Acceleration \( a = 2.0 \, \text{m/s}^2 \)
Check: \( 10.0 = 5.0 \cdot 2.0 \) (Correct)
3. For the third row:
- Net force \( F = 20.0 \, \text{N} \)
- Mass \( m = 5.0 \, \text{kg} \)
- Acceleration \( a = ? \)
Using the formula \( a = \frac{F}{m} \):
\[
a = \frac{20.0 \, \text{N}}{5.0 \, \text{kg}} = 4.0 \, \text{m/s}^2
\]
Thus, the value that would complete the last cell is **4.0**.
From the given data:
1. For the first row:
- Net force \( F = 5.0 \, \text{N} \)
- Mass \( m = 5.0 \, \text{kg} \)
- Acceleration \( a = 1.0 \, \text{m/s}^2 \)
Check: \( 5.0 = 5.0 \cdot 1.0 \) (Correct)
2. For the second row:
- Net force \( F = 10.0 \, \text{N} \)
- Mass \( m = 5.0 \, \text{kg} \)
- Acceleration \( a = 2.0 \, \text{m/s}^2 \)
Check: \( 10.0 = 5.0 \cdot 2.0 \) (Correct)
3. For the third row:
- Net force \( F = 20.0 \, \text{N} \)
- Mass \( m = 5.0 \, \text{kg} \)
- Acceleration \( a = ? \)
Using the formula \( a = \frac{F}{m} \):
\[
a = \frac{20.0 \, \text{N}}{5.0 \, \text{kg}} = 4.0 \, \text{m/s}^2
\]
Thus, the value that would complete the last cell is **4.0**.
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