Use the data given to calculate the value of delta G rxn for the reaction at 25C
2C(graphite)+H2(g)--->C2H2(g)
C H2 C2H2
S(J K^-1 mol^-1)| 5.74 |130.68| 201.0
-------------------
delta H(kJ/mol) | 0 | 0 |-226.8
a.-291.4 kj
b.-244.3 Kj
c.-226.8 kj
d.-207.6 Kj
e.-64.6 Kj
4 answers
Tables, spaces, and the like don't do well on the board. You need to find another format that doesn't require spaces or tables.
Use the data given to calculate the value of delta G rxn for the reaction at 25C
2C(graphite)+H2(g)--->C2H2(g)
C______H2_______C2H2___________________5.74| 130.68| 201.0 | S (JK^-1mol^-1)
_______________________________________
0 | 0 | -226.8|delta H(KJ/mol)
a.-291.4 kj
b.-244.3 Kj
c.-226.8 kj
d.-207.6 Kj
e.-64.6 Kj
2C(graphite)+H2(g)--->C2H2(g)
C______H2_______C2H2___________________5.74| 130.68| 201.0 | S (JK^-1mol^-1)
_______________________________________
0 | 0 | -226.8|delta H(KJ/mol)
a.-291.4 kj
b.-244.3 Kj
c.-226.8 kj
d.-207.6 Kj
e.-64.6 Kj
Thanks for trying but I don't see an improvement over the previous version.
I cant figure out how to do a table :(
Use the data given to calculate the value of delta G rxn for the reaction at 25C
2C(graphite)+H2(g)--->C2H2(g)
C= S(J K^-1) => 5.74 and delta H(kJ/mol)=>0
H2= S(J K^-1)=> 130.68 and delta H (kJ/mol)=>0
C2H2= S(J K^-1)=> 201.0 and delta H(kJ/mol)=> -226.8
a.-291.4 kj
b.-244.3 Kj
c.-226.8 kj
d.-207.6 Kj
e.-64.6 Kj
Use the data given to calculate the value of delta G rxn for the reaction at 25C
2C(graphite)+H2(g)--->C2H2(g)
C= S(J K^-1) => 5.74 and delta H(kJ/mol)=>0
H2= S(J K^-1)=> 130.68 and delta H (kJ/mol)=>0
C2H2= S(J K^-1)=> 201.0 and delta H(kJ/mol)=> -226.8
a.-291.4 kj
b.-244.3 Kj
c.-226.8 kj
d.-207.6 Kj
e.-64.6 Kj