use the data given below to construct a Born-Haber cycle to determine the lattice energy of CaO
Ca(s)--->Ca(g) 193
Ca(g)--->Ca+(g) + e- 590
Ca+(g)--->Ca2+(g) +e- 1010
2O(g)---->02(g) -498
O(g) +e--->0-(g) -141
O-(g) + e---->O2-(g) 878
Ca(s) +1/2 O2(g)---> CaO (s) -635
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http://chemistry.bd.psu.edu/jircitano/BH.html
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2 answers