The cross product is the vector that one can calculate with this determinant:
| i j k |
| 2-1 3 |
| 1 4-2 |
= (2-12) i + (3+4)j + (8+1) k
= -10i +7j +9k
or (-10, 7, 9) in your notation.
That vector, or any vector that is a scalar multiple of it, will be perpendicular to the other two vectors.
Use the cross product to find a vector perpendicular to each of the following pairs of vectors.
(2, -1, 3) and (1, 4, -2)
Can someone please explain this step by step?
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