To find the area of the rectangle formed by the points \( A (1,1) \), \( B (0,2) \), \( C (2,4) \), and \( D (3,3) \), we first need to identify which points are opposite vertices of the rectangle.
Let's examine the coordinates:
- \( A (1, 1) \)
- \( B (0, 2) \)
- \( C (2, 4) \)
- \( D (3, 3) \)
We can find the distances between points to determine the lengths of the sides.
Calculating the distances:
-
Distance between \( A(1, 1) \) and \( B(0, 2) \):
\[
d(AB) = \sqrt{(1 - 0)^2 + (1 - 2)^2} = \sqrt{1^2 + (-1)^2} = \sqrt{1 + 1} = \sqrt{2} \approx 1.414
\]
-
Distance between \( A(1, 1) \) and \( C(2, 4) \):
\[
d(AC) = \sqrt{(1 - 2)^2 + (1 - 4)^2} = \sqrt{(-1)^2 + (-3)^2} = \sqrt{1 + 9} = \sqrt{10} \approx 3.162
\]
-
Distance between \( A(1, 1) \) and \( D(3, 3) \):
\[
d(AD) = \sqrt{(1 - 3)^2 + (1 - 3)^2} = \sqrt{(-2)^2 + (-2)^2} = \sqrt{4 + 4} = \sqrt{8} \approx 2.828
\]
-
Distance between \( B(0, 2) \) and \( C(2, 4) \):
\[
d(BC) = \sqrt{(0 - 2)^2 + (2 - 4)^2} = \sqrt{(-2)^2 + (-2)^2} = \sqrt{4 + 4} = \sqrt{8} \approx 2.828
\]
-
Distance between \( B(0, 2) \) and \( D(3, 3) \):
\[
d(BD) = \sqrt{(0 - 3)^2 + (2 - 3)^2} = \sqrt{(-3)^2 + (-1)^2} = \sqrt{9 + 1} = \sqrt{10} \approx 3.162
\]
-
Distance between \( C(2, 4) \) and \( D(3, 3) \):
\[
d(CD) = \sqrt{(2 - 3)^2 + (4 - 3)^2} = \sqrt{(-1)^2 + (1)^2} = \sqrt{1 + 1} = \sqrt{2} \approx 1.414
\]
From this information, we can assess the arrangement of the points. They do not form a typical rectangle due to the angles formed by them, as the lengths calculated do not indicate opposite equal sides.
If you want to calculate the area of the quadrilateral formed by these points, you can use the Shoelace formula:
\[
\text{Area} = \frac{1}{2} \left| x_1y_2 + x_2y_3 + x_3y_4 + x_4y_1 - (y_1x_2 + y_2x_3 + y_3x_4 + y_4x_1) \right|
\]
Assigning the coordinates:
- \( (x_1, y_1) = (1, 1) \)
- \( (x_2, y_2) = (0, 2) \)
- \( (x_3, y_3) = (2, 4) \)
- \( (x_4, y_4) = (3, 3) \)
Now, substituting into the formula:
\[
\text{Area} = \frac{1}{2} \left| 1 \cdot 2 + 0 \cdot 4 + 2 \cdot 3 + 3 \cdot 1 - (1 \cdot 0 + 2 \cdot 2 + 4 \cdot 3 + 3 \cdot 1) \right|
\]
Calculating:
\[
= \frac{1}{2} \left| 2 + 0 + 6 + 3 - (0 + 4 + 12 + 3) \right|
\]
\[
= \frac{1}{2} \left| 11 - 19 \right|
\]
\[
= \frac{1}{2} \left| -8 \right| = 4
\]
Thus, the approximate area of the quadrilateral formed by the points is 4 square units.