Use the Commutative Property of Multiplication to rewrite the algebraic expression: j^37⋅h^24

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11 answers

The Commutative Property of Multiplication states that the order of multiplication does not affect the product. Therefore, you can rearrange the factors in the expression \( j^{37} \cdot h^{24} \).

Using the Commutative Property, the expression can be rewritten as:

\[ h^{24} \cdot j^{37} \]

Both forms represent the same value, but the order of the factors has changed.

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Question
Use the Distributive Property to rewrite the expression (2x−2)(x−6)
.(1 point)
Responses

2x2+10x−10
2 x squared plus 10 x minus 10

3x2−10x−8
3 x squared minus 10 x minus 8

x2−8x+12
x squared minus 8 x plus 12

2x2−14x+12

To use the Distributive Property to rewrite the expression \((2x - 2)(x - 6)\), we will distribute each term in the first parentheses across each term in the second parentheses:

\[ (2x - 2)(x - 6) = 2x \cdot x + 2x \cdot (-6) - 2 \cdot x - 2 \cdot (-6) \]

Calculating each term:

  1. \(2x \cdot x = 2x^2\)
  2. \(2x \cdot (-6) = -12x\)
  3. \(-2 \cdot x = -2x\)
  4. \(-2 \cdot (-6) = 12\)

Now, combine these results:

\[ 2x^2 - 12x - 2x + 12 \]

Combine the like terms for \(x\):

\[ 2x^2 - 14x + 12 \]

So, the expression \((2x - 2)(x - 6)\) can be rewritten as:

2x² - 14x + 12

Thus, the correct response from your provided options is:

2x² − 14x + 12.

What is (a^2−11)+(3a^2−4a+6)
?(1 point)
Responses

−5
negative 5

−4a2+4a+5
negative 4 a squared plus 4 a plus 5

3a2−4a−5
3 a squared minus 4 a minus 5

4a2−4a−5

To simplify the expression \((a^2 - 11) + (3a^2 - 4a + 6)\), we can combine like terms.

  1. First, distribute the addition across the terms: \[ a^2 - 11 + 3a^2 - 4a + 6 \]

  2. Now, combine like terms:

    • For \(a^2\) terms: \(a^2 + 3a^2 = 4a^2\)
    • For \(a\) terms: There is only one \(-4a\)
    • For constant terms: \(-11 + 6 = -5\)

Putting it all together, we have: \[ 4a^2 - 4a - 5 \]

Thus, the correct response from your provided options is:

4a² − 4a − 5.

Multiply the polynomials (2r−5)(r+4)
.(2 points)
r^2+
r+

To multiply the polynomials \((2r - 5)(r + 4)\), we can use the distributive property (often referred to as FOIL for binomials):

  1. First: Multiply the first terms in each polynomial: \[ 2r \cdot r = 2r^2 \]

  2. Outer: Multiply the outer terms: \[ 2r \cdot 4 = 8r \]

  3. Inner: Multiply the inner terms: \[ -5 \cdot r = -5r \]

  4. Last: Multiply the last terms: \[ -5 \cdot 4 = -20 \]

Now, combine all these results: \[ 2r^2 + 8r - 5r - 20 \]

Combine like terms (\(8r - 5r\)): \[ 2r^2 + 3r - 20 \]

So, the final result of multiplying \((2r - 5)(r + 4)\) is: \[ 2r^2 + 3r - 20 \]

In the format you provided:

  • \(r^2 + 3r - 20\)
? r^2+ ?r+?

From the multiplication of the polynomials \((2r - 5)(r + 4)\), we derived the expanded form:

\[ 2r^2 + 3r - 20 \]

To fit it into the format you provided:

  • For \(r^2\), the coefficient is 2.
  • For \(r\), the coefficient is 3.
  • The constant term is −20, but since you are asking for \(r^2 + ?r + ?\), it seems you want just the coefficients of \(r^2\) and \(r\).

Thus, the corresponding values would be:

  • \(r^2 + 3r + (-20)\)

So, you can fill in the blanks as follows:

  • First blank (coefficient of \(r^2\)): 2
  • Second blank (coefficient of \(r\)): 3
  • Third blank (constant term): -20

Putting it all together:

  • \(2r^2 + 3r - 20\) corresponds to:
    • 2 (for \(r^2\))
    • 3 (for \(r\))
    • −20 (constant term)

If you want it in the blanks format:
2, 3, -20.

Which of the following values for n makes the inequality 2n−−√<5
true?(1 point)
Responses

12.5
12.5

18
18

16
16

8

To solve the inequality \( \sqrt{2n} < 5 \), we will isolate \( n \).

  1. First, square both sides to eliminate the square root: \[ 2n < 5^2 \] This simplifies to: \[ 2n < 25 \]

  2. Now, divide both sides by 2: \[ n < \frac{25}{2} \] This simplifies to: \[ n < 12.5 \]

Now we can check the given values to see which ones satisfy the inequality \( n < 12.5 \):

  • 12.5: Does not satisfy \( n < 12.5 \) (it is equal, not less than).
  • 18: Does not satisfy \( n < 12.5 \).
  • 16: Does not satisfy \( n < 12.5 \).
  • 8: Satisfies \( n < 12.5 \) (8 is less than 12.5).

Therefore, the value for \( n \) that makes the inequality true is:

8.