Use the chemical reaction to answer the question.

Question

​CaCO3→CO2​+CaO

A scientist heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown. What is the total mass of the products?

Answer 1

According to the chemical reaction, 1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO.

The molar mass of CaCO3 is 100.0869 g/mol.

Therefore, the number of moles of CaCO3 in 30 grams is:
30 g / 100.0869 g/mol = 0.2997 mol of CaCO3

Since the mole ratio is 1:1:1, the number of moles of CO2 and CaO produced is also 0.2997 mol each.

The molar mass of CO2 is 44.01 g/mol and the molar mass of CaO is 56.0774 g/mol.

Therefore, the total mass of the products is:
(0.2997 mol of CO2) x (44.01 g/mol) + (0.2997 mol of CaO) x (56.0774 g/mol)
= 13.199 g + 16.814 g
= 29.013 g

The total mass of the products is approximately 29.013 grams.

Answer 2

That’s incorrect

Answer 3

I apologize for the incorrect response. Let's go through the calculation again:

The molar mass of CaCO3 is 100.0869 g/mol. Therefore, 30 grams of CaCO3 is equal to:

30 g / 100.0869 g/mol = 0.2997 mol of CaCO3

According to the chemical reaction, 1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO. So, the number of moles of CO2 and CaO produced is also 0.2997 mol each.

The molar mass of CO2 is 44.01 g/mol and the molar mass of CaO is 56.0774 g/mol.

Therefore, the total mass of the products is:

(0.2997 mol of CO2) x (44.01 g/mol) + (0.2997 mol of CaO) x (56.0774 g/mol)
= 13.18 g + 16.81 g
= 29.99 g

So, the correct total mass of the products is approximately 29.99 grams.