Law of conservation of mass.
mass CO2 + mass CaO = 30 g products = mass reactants = 30 g CaCO3.
Use the chemical reaction to answer the question.
CaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown. What is the total mass of the products?
(1 point)
2 answers
You can prove this by stoichiometry .
mols CaCO3 = grams/molar mass = 30/100 = 0.30
1 mole CaCO3 forms 1 mols CaO so 0.30 mols CaO.
grams CaO = moles CaO x molar mass CaO = 0.30 x 56 = 16.8 g
1 mol CaCO3 forms 1 mol CO2 = 0.30 mols CO2 formed.
grams CO2 = mols x molar mass = 0.30 x 44 = 13.2 g
total mass products = 16.8 + 13.2 = 30
mass reactants = 30 g = mass products
What goes in must come out.
mols CaCO3 = grams/molar mass = 30/100 = 0.30
1 mole CaCO3 forms 1 mols CaO so 0.30 mols CaO.
grams CaO = moles CaO x molar mass CaO = 0.30 x 56 = 16.8 g
1 mol CaCO3 forms 1 mol CO2 = 0.30 mols CO2 formed.
grams CO2 = mols x molar mass = 0.30 x 44 = 13.2 g
total mass products = 16.8 + 13.2 = 30
mass reactants = 30 g = mass products
What goes in must come out.