The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol.
Using the molar masses of the products:
- CO2 has a molar mass of 44.01 g/mol
- CaO has a molar mass of 56.08 g/mol
To find the total mass of the products, we first need to calculate the moles of CaCO3 in 30 grams:
30 g / 100.09 g/mol = 0.2996 moles
Now, we use the mole ratio from the balanced chemical equation to determine the moles of CO2 and CaO produced. From the chemical equation, we see that 1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO:
0.2996 moles CaCO3 * 1 mole CO2 / 1 mole CaCO3 = 0.2996 moles CO2
0.2996 moles CaCO3 * 1 mole CaO / 1 mole CaCO3 = 0.2996 moles CaO
Now, we calculate the masses of the products:
- Mass of CO2 = 0.2996 moles * 44.01 g/mol = 13.18 grams
- Mass of CaO = 0.2996 moles * 56.08 g/mol = 16.77 grams
Therefore, the total mass of the products (CO2 and CaO) is 13.18 grams + 16.77 grams = 29.95 grams.
Use the chemical reaction to answer the question.
CaCO3 CO2 +CaO
A scientist heats 30 grams of calcium carbonate ( CaCO3 ) in the chemical reaction shown. What is the total mass of the products?
1 answer