To perform the calculations you've mentioned, I'll guide you through the steps required for each task using typical values based on your prompts. However, since I can't directly access or click on any external calculators, I'll provide the expected calculations for you.
Car Loan Calculations
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Auto Loan Amount: $20,000
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Payments at Different Interest Rates:
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7% Interest Rate for 5 years: To calculate the monthly payment, you can use the formula for an amortizing loan:
\[ M = P \times \frac{r(1+r)^n}{(1+r)^n - 1} \]
Where:
- \( M \) = total monthly payment
- \( P \) = principal loan amount ($20,000)
- \( r \) = monthly interest rate (annual rate / 12)
- \( n \) = number of payments (loan term in months)
At 7% interest:
- Monthly interest rate \( r = \frac{0.07}{12} \approx 0.005833 \)
- Number of payments \( n = 5 \times 12 = 60 \)
- Plugging in the values:
\[ M = 20000 \times \frac{0.005833(1 + 0.005833)^{60}}{(1 + 0.005833)^{60} - 1} \approx $396.24 \]
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11% Interest Rate for 5 years: At 11% interest:
- Monthly interest rate \( r = \frac{0.11}{12} \approx 0.009167 \)
- Plugging in the values:
\[ M = 20000 \times \frac{0.009167(1 + 0.009167)^{60}}{(1 + 0.009167)^{60} - 1} \approx $425.45 \]
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Difference in Payments: \[ Difference = 425.45 - 396.24 \approx $29.21 \]
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Mortgage Calculations
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Monthly Payment for a House:
- House Price: $200,000
- Interest Rate: 8%
- Loan Term: 30 years (360 months)
Using the same formula as above:
- Monthly interest rate \( r = \frac{0.08}{12} \approx 0.006667 \)
- Plugging in the values:
\[ M = 200000 \times \frac{0.006667(1 + 0.006667)^{360}}{(1 + 0.006667)^{360} - 1} \approx $1,467.53 \]
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Total Amount of Interest Paid:
- Total payment over 30 years: \( M \times n = 1,467.53 \times 360 \approx $528,109.80 \)
- Total interest paid:
\[ Total Interest = Total Payment - Principal = 528,109.80 - 200,000 \approx $328,109.80 \]
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New Payment at 5% Interest Rate:
- Monthly interest rate \( r = \frac{0.05}{12} \approx 0.004167 \)
- Plugging in the values:
\[ M = 200000 \times \frac{0.004167(1 + 0.004167)^{360}}{(1 + 0.004167)^{360} - 1} \approx $1,073.64 \]
Total Interest Paid:
- Total payment over 30 years: \( 1,073.64 \times 360 \approx $386,914.40 \)
- Total interest paid:
\[ Total Interest = 386,914.40 - 200,000 \approx $186,914.40 \]
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Payment and Total Interest Paid with 5% for 15 Years:
- New loan term: 15 years (180 months)
- Monthly interest rate \( r = \frac{0.05}{12} \approx 0.004167 \)
- Plugging in the values:
\[ M = 200000 \times \frac{0.004167(1 + 0.004167)^{180}}{(1 + 0.004167)^{180} - 1} \approx $1,588.53 \]
Total Interest Paid:
- Total payment over 15 years: \( 1,588.53 \times 180 \approx $285,936.40 \)
- Total interest paid:
\[ Total Interest = 285,936.40 - 200,000 \approx $85,936.40 \]
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Difference in Interest Paid:
- From question 5: \( 186,914.40 \)
- From question 6: \( 85,936.40 \)
- Difference:
\[ Difference = 186,914.40 - 85,936.40 = 100,978.00 \]
Summary
- Car Loan Difference: $29.21
- Mortgage Payments:
- At 8% for 30 years: $1,467.53 total interest: $328,109.80
- At 5% for 30 years: $1,073.64 total interest: $186,914.40
- At 5% for 15 years: $1,588.53 total interest: $85,936.40
- Interest Difference (30yrs 5% and 15yrs 5%): $100,978.00
The calculations demonstrate how interest significantly affects the total loan cost over time. High interest rates and long loan durations can lead to substantial amounts paid in interest.