Use the balanced equation for the reaction of lithium oxide with water:

Question

Li2O(s) + H2O(g) --> 2LiOH(s)
to determine how many grams of H2O can be removed from the air by 250g of Li2O. Show your step-by-step solution with unit conversions.

Answer 1

Step 1: Convert 250g of Li2O to moles

250g Li2O x (1 mol Li2O/22.99g Li2O) = 10.9 moles Li2O

Step 2: Use the mole ratio from the balanced equation to determine the moles of H2O

10.9 moles Li2O x (1 mol H2O/2 mol Li2O) = 5.45 moles H2O

Step 3: Convert moles of H2O to grams

5.45 moles H2O x (18.02g H2O/1 mol H2O) = 97.7g H2O