To use the arithmetic sequence formula \( a_n = 5 + (n - 1) \cdot 2 \), we need to evaluate the formula for the specified values of \( n \).
The formula represents an arithmetic sequence where:
- \( a_n \) is the value of the nth term,
- \( 5 \) is the first term,
- \( 2 \) is the common difference.
Now let's complete the table for \( n = 2 \) and \( n = 4 \):
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For \( n = 2 \): \[ a_2 = 5 + (2 - 1) \cdot 2 = 5 + 1 \cdot 2 = 5 + 2 = 7 \]
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For \( n = 4 \): \[ a_4 = 5 + (4 - 1) \cdot 2 = 5 + 3 \cdot 2 = 5 + 6 = 11 \]
Now we can fill in the table:
\[ \begin{array}{|c|c|} \hline x & y \ \hline 2 & 7 \ 4 & 11 \ \hline \end{array} \]
So the completed values are:
- When \( x = 2 \), \( y = 7 \).
- When \( x = 4 \), \( y = 11 \).