To find the missing values in the table using the arithmetic sequence formula \( a_n = 5 + (n-1) \cdot 2 \), we will substitute the values for \( n \) corresponding to \( x \) values.
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For \( x = 2 \): \[ a_2 = 5 + (2-1) \cdot 2 = 5 + 1 \cdot 2 = 5 + 2 = 7 \] So, \( y \) when \( x = 2 \) is \( 7 \).
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For \( x = 4 \): \[ a_4 = 5 + (4-1) \cdot 2 = 5 + 3 \cdot 2 = 5 + 6 = 11 \] So, \( y \) when \( x = 4 \) is \( 11 \).
Now, filling in the table:
\[ \begin{array}{|c|c|} \hline x & y \ \hline 2 & 7 \ 4 & 11 \ \hline \end{array} \]