To compute \(-12 \frac{2}{3} - (-8 \frac{5}{6})\), we can first rewrite the expression to remove the double negative:
\[
-12 \frac{2}{3} + 8 \frac{5}{6}
\]
Next, let's convert the mixed numbers into improper fractions:
-
Convert \(-12 \frac{2}{3}\):
\[
-12 \frac{2}{3} = -\left(12 \times 3 + 2\right)/3 = -\left(36 + 2\right)/3 = -\frac{38}{3}
\]
-
Convert \(8 \frac{5}{6}\):
\[
8 \frac{5}{6} = \left(8 \times 6 + 5\right)/6 = \left(48 + 5\right)/6 = \frac{53}{6}
\]
Now we have:
\[
-\frac{38}{3} + \frac{53}{6}
\]
To add these fractions, we need a common denominator. The least common multiple of 3 and 6 is 6. So we can convert \(-\frac{38}{3}\) to a fraction with a denominator of 6:
\[
-\frac{38}{3} = -\frac{38 \times 2}{3 \times 2} = -\frac{76}{6}
\]
Now we can add:
\[
-\frac{76}{6} + \frac{53}{6} = \frac{-76 + 53}{6} = \frac{-23}{6}
\]
So, the final result is:
\[
-12 \frac{2}{3} - (-8 \frac{5}{6}) = -\frac{23}{6}
\]
If you'd like to express \(-\frac{23}{6}\) as a mixed number, it would be:
\[
-3 \frac{5}{6}
\]
Thus, the final answer can be written in either improper fraction or mixed number form:
\[
\text{-}\frac{23}{6} \quad \text{or} \quad -3 \frac{5}{6}
\]