To find the sum of \(-24 \frac{4}{5}\) and \(-6 \frac{7}{10}\) using the additive inverse, we will first convert mixed numbers into improper fractions and then find their sum.
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Convert the mixed numbers to improper fractions:
- For \(-24 \frac{4}{5}\): \[ -24 \frac{4}{5} = -\left(24 \times 5 + 4\right) / 5 = -\frac{120 + 4}{5} = -\frac{124}{5} \]
- For \(-6 \frac{7}{10}\): \[ -6 \frac{7}{10} = -\left(6 \times 10 + 7\right) / 10 = -\frac{60 + 7}{10} = -\frac{67}{10} \]
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Find a common denominator to add the fractions:
- The least common denominator (LCD) of 5 and 10 is 10. Convert \(-\frac{124}{5}\) to have a denominator of 10: \[ -\frac{124}{5} = -\frac{124 \times 2}{5 \times 2} = -\frac{248}{10} \]
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Add the two fractions: \[ -\frac{248}{10} + -\frac{67}{10} = -\frac{248 + 67}{10} = -\frac{315}{10} \]
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Simplify \(-\frac{315}{10}\) to a mixed number: \[ -\frac{315}{10} = -31 \frac{5}{10} = -31 \frac{1}{2} \]
Thus, the final answer is:
\[ \boxed{-31 \frac{1}{2}} \]
Among your options, the correct response is: \(-31 \frac{1}{2}\).