I will try to line up the numbers,
2 │ 1 -7 12 3
...------------
.......2 -10 6
....1 -5 ..3 9
so (x^3-7x^2+13x+3)/(x-2)
= x^2-5x+3 + 9/(x-2)
Use synthetic division to find the quotient and the remainder of:
(x^3-7x^2+13x+3)/(x-2)
2 answers
Do we add the 9 and 3 to get 12??
=x^2 -5x (12/x-2)
=x^2 -5x (12/x-2)