hard to explain synthetic division here. If you know how to do it, then you just need to know that
p(3) is the remainder after doing the division.
That's because p(x) = (x-3)*q(x) + p(3)
If x-3 divides p(x), then there is no remainder: p(3) = 0.
Use synthetic division to find P(3) for P(x)=x^4-6x^3-4x^2-6x-2
Can someone please explain
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