First, solve the first equation for y:
-2x + y = -2
y = 2x - 2
Now substitute this into the second equation:
3x + 5(2x - 2) = 29
3x + 10x - 10 = 29
13x - 10 = 29
13x = 39
x = 3
Now that we have x, we can substitute it back into y = 2x - 2 to find y:
y = 2(3) - 2
y = 6 - 2
y = 4
Therefore, the solution to the system is x = 3 and y = 4.
Use substitution to solve the system. -2x+y=-2 and 3x+5y=29
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