Rydberg equation?
1/lambda=R (1/n1^2- 1/n2^2)
N2=infinity
N1=3
solve for lambda
Use Rydbuz equation to calculate the
wavelength of the third line in the paschen
series of the hydrogen spectrum.give ur
answer in Nm.
RH=2.18 * 10^-18j,
H=6.63 * 10^-34J.
Plz help m
2 answers
1 / λ = R [(1 / n₁^2) - (1 / n₂^2)]
R = 1.097 x 10⁷ m⁻¹
the starting principle quantum number (n₁) for the Paschen Series is 3
the number (n₂) for the 3rd line is 6
R = 1.097 x 10⁷ m⁻¹
the starting principle quantum number (n₁) for the Paschen Series is 3
the number (n₂) for the 3rd line is 6