To simplify the expression \(\frac{\sqrt{49}}{7^{-3}}\) using the quotient property and negative exponent property, we start by simplifying the components.
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Simplifying \(\sqrt{49}\): \[ \sqrt{49} = 7 \]
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The expression now becomes: \[ \frac{7}{7^{-3}} \]
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Applying the quotient property of exponents, which states that \(\frac{a^m}{a^n} = a^{m-n}\): \[ \frac{7^1}{7^{-3}} = 7^{1 - (-3)} = 7^{1 + 3} = 7^4 \]
Now, \(7^4\) is the simplified expression.
To express \(7^4\) in terms of rational exponents, we can write: \[ 7^4 = 7^{\frac{4}{1}} \]
So, the rational exponent for the new expression is: \[ \frac{4}{1} \] and the final answer is: \[ 7^4 \]