Use quadratic formula to solve each equation 3k^2+6=6

Question

I get 3/2 but I can't seem to get the other half of the equation such as x=3.7 or .26 etc...

Answer 1

i think you mean 3k^2 + 6k = 6
thus, we can re write this as
3k^2 + 6k - 6 = 0
note that we can factor out 3 from each term and cancel it. thus we can re write this as
k^2 + 2k - 2 = 0
using quadratic formula,
k = [-b +- sqrt(b^2 - 4ac)]/(2a)
substituting,
k = [-2 +- sqrt(2^2 - 4*1*(-2))]/(2*1)
k = [-2 +- sqrt(4 + 8)]/2
k = [-2 +- sqrt(12)]/2
k = [-2 +- 2*sqrt(3)]/2
k = -1 +- sqrt(3)
separating into plus and minus,
k = -1 + sqrt(3) and k = -1 - sqrt(3)

hope this helps~ :)

Answer 2

no.. there is no 6 in front of the k at least not in my text book