Use proportional relationships to solved this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students?

Options:
200 students
124 students
259 students
50 students

3 answers

Let's assume the number of seats in the band is "x". Since the number of seats in choir is 4 times the number of seats in the band, the number of seats in choir would be 4x.

According to the problem, the total number of students is 250. So, the number of students who can choose band would be x.

We can set up a proportion to solve for x:

x/4x = 250/1

Cross-multiplying, we get:

1 * x = 4x * 250

x = (4x * 250)/1

x = 1000x

Dividing both sides by x:

1 = 1000

This is not possible, so there is no solution that satisfies the given conditions.

Therefore, none of the given options (200 students, 124 students, 259 students, 50 students) are correct.
Which one
Apologies for the confusion. It seems that I made an error in my calculations.
Let's approach the problem again:

We know that there are four times as many seats in choir as there are in the band. Let's say the number of seats in the band is "x". Therefore, the number of seats in the choir would be 4x.

We also know that the total number of students is 250.

To find out how many students can choose band, we need to determine the value of x.

Since the ratio of the number of seats in choir to the number of seats in the band is 4:1, we can set up the following proportion:

4x/x = 250/1

Cross-multiplying, we get:

4x = 250

Dividing both sides by 4:

x = 250/4

x = 62.5

We can't have a fraction of a seat, so we need to round down to the nearest whole number:

x = 62

Therefore, the number of students that can choose band is 62.

Among the given options (200 students, 124 students, 259 students, 50 students), the closest one is 50 students. So the correct option is:

50 students