Let \( b \) be the number of students who choose band, and \( c \) be the number of students who choose choir. According to the problem, we have the following relationships:
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There are four times as many seats in choir as there are in band: \[ c = 4b \]
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The total number of students choosing band or choir is 250: \[ b + c = 250 \]
Now we can substitute the first equation into the second equation:
\[ b + 4b = 250 \]
This simplifies to:
\[ 5b = 250 \]
Next, solving for \( b \):
\[ b = \frac{250}{5} = 50 \]
Thus, the number of students who can choose band is \( \boxed{50} \).