Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students?(1 point) Responses 50 students 50 students 124 students 124 students 200 students 200 students 250 students

Answer 1

To solve the problem, let's define the number of students who choose band as \( b \) and the number of students who choose choir as \( c \).

From the problem, we know:

1. The total number of students is 250.
2. There are four times as many seats in choir as there are in band, which means \( c = 4b \).

Now, we can set up the equation based on the total number of students:

\[ b + c = 250 \]

Substituting the expression for \( c \):

\[ b + 4b = 250 \]

Now, combine the terms:

\[ 5b = 250 \]

To find \( b \), divide both sides by 5:

\[ b = \frac{250}{5} = 50 \]

Thus, the number of students who can choose band is \( \boxed{50} \).