Let the number of students choosing band be \( b \) and the number of students choosing choir be \( c \).
According to the problem, we know two things:
- The total number of students is 250: \[ b + c = 250 \]
- There are four times as many seats in choir as there are in band: \[ c = 4b \]
Now we can substitute the second equation into the first equation: \[ b + 4b = 250 \]
Combining like terms gives: \[ 5b = 250 \]
Now, divide both sides by 5: \[ b = \frac{250}{5} = 50 \]
Thus, the number of students that can choose band is 50 students.
The correct response is: 50 students.