To solve this problem using proportional relationships, we can set up a proportion comparing the number of seats in choir to the number of seats in band.
Let's represent the number of seats in choir as "C" and the number of seats in band as "B".
We know that there are four times as many seats in choir as there are in band, so we can write the following proportion:
C/B = 4/1
If we can find the value of C, we can then subtract it from the total number of students to find the number of students who can choose band.
To solve the proportion, we can cross multiply:
C = 4B
Since we know that the total number of students is 250, we can write the following equation:
C + B = 250
Substituting the value of C from the proportion into the equation:
4B + B = 250
5B = 250
Dividing both sides of the equation by 5:
B = 50
Therefore, the number of students who can choose band is 50.
The correct answer is:
50 students.
Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students? (1 point)
200 students
250 students
124 students
50 students
1 answer