use properties of operations to factor 8w+16 using GCF

Question

a. 8(w+2)
b. 2(4w+8)
c. 6 (2w+10)
d. 4(2w+4)

Answer 1

The correct answer is b. 2(4w+8)

Answer 2

Factor -27h+6 using the GCF
a. 3(9h+2)
b. 3(-9h+2)
c. 3(-9h+2)
d. 3(-9h-2)

Answer 3

To factor -27h+6 using the GCF, we first need to find the greatest common factor (GCF) of -27 and 6. The GCF of -27 and 6 is 3.

Next, we divide each term in -27h+6 by the GCF of 3:
(-27h + 6) / 3 = -9h + 2

So the factored form of -27h+6 using the GCF is 3(-9h+2). The correct answer is a. 3(9h+2).

Answer 4

expand and distribute -5(-3-11g)
a. 55g-15
b. -55g-15
c. -55g+15
d. 55g+15

Answer 5

To expand and distribute -5(-3-11g), we need to distribute the -5 to both terms inside the parentheses:

-5(-3-11g) = -5 * -3 - 5 * (-11g) = 15 + 55g = 55g + 15

So the correct answer is d. 55g + 15.

Answer 6

simplify by combining like terms 2/8x + 3/10y - 5/8x + 4/10 y

a. 14/18 xy
b -3/8x + 7/10y
c. 4/18xy
d. 7/10x + 7/8y

Answer 7

To simplify the expression 2/8x + 3/10y - 5/8x + 4/10y, we combine like terms by adding or subtracting coefficients that have the same variable.

First, let's combine the terms with x: 2/8x - 5/8x = (2-5)/8x = -3/8x

Next, let's combine the terms with y: 3/10y + 4/10y = (3+4)/10y = 7/10y

Therefore, the simplified expression is -3/8x + 7/10y.

The correct answer is b. -3/8x + 7/10y.

Answer 8

evaluate when a=9, b=6
a-b/3
a. 6
b.9
c. 3
d. 1

Answer 9

To evaluate the expression a-b/3 when a=9 and b=6, we substitute the given values into the expression:

a-b/3 = 9 - 6/3

Now, we simplify:

9 - 6/3 = 9 - 2 = 7

So, when a=9 and b=6, the value of a-b/3 is 7.

The correct answer is none of the given options.

Answer 10

evaluate the problem (a-b/3) when a=9, b=6

a. 6
b.9
c.3
d.1

Answer 11

To evaluate the expression (a-b/3) when a=9 and b=6, we substitute the given values into the expression:

(a-b/3) = (9-6/3)

Now, we simplify:

(9-6/3) = (9-2) = 7

So, when a=9 and b=6, the value of (a-b/3) is 7.

The correct answer is none of the given options.