Asked by MV
Use properties of logartithms to simplify and solve. Thanks.
ln(x-3)-ln(11x-23)+in(x-1)=0
ln(x-3)-ln(11x-23)+in(x-1)=0
Answers
Answered by
MV
I believe it may be x=2,x=13
Answered by
Reiny
Did you test your answers?
Obviously x= 2 cannot be right since it would make
the second term undefined,
ln(22-23) = ln(-1), which is undefined
using the rules of logs, we get
ln[(x-3)(x-1)/(11x - 23) ] = 0
(x-3)(x-1)/(11x - 23) = e^0 = 1
x^2 - 4x + 3 = 11x - 23
x^2 - 15x+ 26 = 0
(x-2)(x-13) = 0
so x=2 or x=13
check for x=13
LS = ln10 - ln120 + ln12
= ln(10(12)/120) = ln 1 = 0 = RS
x = 13
Obviously x= 2 cannot be right since it would make
the second term undefined,
ln(22-23) = ln(-1), which is undefined
using the rules of logs, we get
ln[(x-3)(x-1)/(11x - 23) ] = 0
(x-3)(x-1)/(11x - 23) = e^0 = 1
x^2 - 4x + 3 = 11x - 23
x^2 - 15x+ 26 = 0
(x-2)(x-13) = 0
so x=2 or x=13
check for x=13
LS = ln10 - ln120 + ln12
= ln(10(12)/120) = ln 1 = 0 = RS
x = 13
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.