use pascal's triangle to expand the expression

(2x-3y)^3

2 answers

the coefficients are 1,3,3,1 so you have

1(2x)^3(-3y)^0 + 3(2x)^2(-3y)^1 + 3(2x)^1(-3y)^2 + 1(2x)^0(-3y)^3

= 8x^3 - 36x^2y + 54xy^2 - 27y^3
thank you
Similar Questions
  1. Use Pascal's triangle to expand the expression.(x − y)5 so I tried to work this out: (x-y)^5 = [(x-y)(x-y)][(x-y)(x-y)](x-y)
    1. answers icon 1 answer
  2. 1)Use Pascal's triangle to expand (w-x)^52)Use the binomial theorem to find the third term in the expression of (n-2p)^6 3)Which
    1. answers icon 1 answer
  3. 1) expand (1+3x)^4 using the Binomial Theorem.2) Use Pascal's Triangle to expand(x+2)^5 3)What is the third term of (a+b)^11?
    1. answers icon 1 answer
    1. answers icon 8 answers
more similar questions